Question

Hello!I need help on my final exam review packet.#42 #43 and #45

Answer 1

Recall that to evaluate a function at a given value, we substitute the variable by the given value.

Therefore:

For x=2 we get:

$y=-2\cdot2-2=-4-2=-6.$

For x=1 we get:

$y=-2\cdot1-2=-2-2=-4.$

For x=0 we get:

$y=-2\cdot0-2=0-2=-2.$

Therefore the y-intercept has coordinates (0,-2).

For x= -1 we get:

$y=-2(-1)-2=2-2=0.$

Therefore the x-intercept has coordinates (-1,0).

For x=-2 we get:

$y=-2(-2)-2=4-2=2.$

For x=50 we get:

$y=-2(50)-2=-100-2=-102.$

Therefore (50,-102) is a solution to the given equation.

Answer:

Since at x=50, y=-102 we get that the point (50,-102) is a solution t the given equation.

The x-intercept is (-1,0).

The y-intercept is (0,-2).