Given:
[tex]f(x)=3x,g(x)=\frac{1}{3}x[/tex]Required:
We need to find f(g(x)) and g(f(x)).
Explanation:
[tex]Substitute\text{ }g(x)=\frac{1}{3}x\text{ in the }f(g(x)).[/tex][tex]f(g(x))=f(\frac{1}{3}x)[/tex][tex]Replace\text{ }x=\frac{1}{3}x\text{ in the equation }f(x)=3x.[/tex][tex]f(\frac{1}{3}x)=3(\frac{1}{3}x)[/tex][tex]f(\frac{1}{3}x)=x[/tex][tex]Substitute\text{ f}(\frac{1}{4}x)=x\text{ in the }f(g(x))=f(\frac{1}{3}x).[/tex][tex]f(g(x))=x[/tex][tex]Substitute\text{ f}(x)=3x\text{ in the }g(f(x)).[/tex][tex]g(f(x))=g(3x)[/tex][tex]Replace\text{ }x=3x\text{ in the equation }g(x)=\frac{1}{3}x.[/tex][tex]g(3x)=\frac{1}{3}(3x)[/tex][tex]g(3x)=x[/tex][tex]Substitute\text{ }g(3x)=x\text{ in }the\text{ equation }g(f(x))=g(3x).[/tex][tex]\text{ }g(f(x))=x[/tex][tex]If\text{ }f(g(x))=g(f(x))=x\text{ then f and g are inverse functions.}[/tex]Final answer:
[tex]f(g(x))=x[/tex][tex]f(g(x))=x[/tex][tex]\text{f and g are inverse functions.}[/tex]