Question

How many kilograms of tight B are there in one bag, in part a is a plus or minus and part B how much does B equal

Answer 1

Let the number of kilograms of type B in 1 bag of blend be b

Given:

(a) There are 4kg of type A in 1 bag

Total kg in 6 bags is 48

Hence:

$\begin{gathered} =\text{ 6 }\times\text{ 4} \\ =\text{ 24} \end{gathered}$

There would be 24kg of type A in 6 bags

Similarly for type B:

$\begin{gathered} =\text{ 6 }\times\text{ b} \\ =\text{ 6b} \end{gathered}$

There would be 6b kg of type B in 6 bags

The sum of the of kg of type A and type B in 6 bags is equal to 48

$\begin{gathered} 24\text{ + 6b = 48} \\ 6(b\text{ + 4) = 48} \end{gathered}$

Answer: 6(b + 4) = 48

(b) The number of kilograms of type B in 1 bag

Solving the equation above, we have:

$\begin{gathered} 6(b\text{ + 4) = 48} \\ \text{Divide through by 6} \\ b\text{ + 4 = }\frac{48}{6} \\ b\text{ + 4 = 8} \\ b\text{ = 8 - 4} \\ b\text{ = 4} \end{gathered}$

Hence, there are 4kg of type B in 1 bag

Answer: b = 4