Respuesta :

In this case, we have te equation of a line, the general form of a linear equation looks like this:

y=mx+b

where m is the slope of the line and b is its intercept.

Now let's make our equation to look like the general formula, we can do this by adding y and subtracting 3 in both sides, like this:

[tex]\begin{gathered} 3x-y=3 \\ 3x-y+y-3=3-3+y \\ 3x-3=y \end{gathered}[/tex]

Now, as we can see the value of the slope of our line is 3, and its intercept is also 3.

Now, when we want to plot a line we just have to find two points of it, we can find these points by replacing x into the equation and calculating it's y value, for example, let's do it with x equals 0 and x equals 1:

[tex]\begin{gathered} y(0)=3\times0+3=3 \\ y(1)=3\times1+3=6 \end{gathered}[/tex]

Now we know two points of the line, (0,3) and (1,6), let's plot them and connect them with the line

Ver imagen AnnekaG446426
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