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[tex]\begin{gathered} \text{ x}^2\text{ - 5 = 2x} \\ x^2\text{ - 2x - 5 = 0 } \\ x^2\text{ -2x = 5} \\ x^2-2x+(1)^2\text{ = 5} \\ (x-1)^2\text{ = 5} \\ (x\text{ - 1) = }\sqrt[]{5} \\ x\text{ = }\sqrt[\square]{5}\text{ + 1} \\ x\text{ = 1 - }\sqrt[]{5} \end{gathered}[/tex]It has two real solutions
