Answer:
[tex]v^u=45[/tex]Explanation:
Given the logarithm form of the expression:
[tex]\log _v45=u[/tex]To write it in exponential form, the following applies:
0. The Base becomes the base of the index form.
,1. The number on the other side of the log operator becomes the index.
,2. The number whose log is being found is the answer.
Therefore, the exponential form is:
[tex]\begin{gathered} v^u=45 \\ v\text{ raised to the power of u = 45} \end{gathered}[/tex]The diagram below is an illustration: