Question

1. Re-arrange the Ohm’s Law equation to solve the following:I = Type your answers here.R = Type your answers here.2. Power is equal to voltage multiplied by current. Add the missing information in each of the following power equations.P = V Type your answers here.P = R Type your answers here.P = V2 Type your answers here.

Answer 1

$\begin{gathered} 1)I=\frac{V}{R} \\ R=\frac{V}{I} \end{gathered}$

2)

$\begin{gathered} P=VI \\ P=RI^2 \\ P=\frac{V^2}{R} \end{gathered}$

Explanation

Step 1

Ohm's law states that the strength of a direct current is directly proportional to the potential difference and inversely proportional to the resistance of the circuit.

$I=\frac{V}{R}$

so

a)

$I=\frac{V}{R}$

b)

$\begin{gathered} I=\frac{V}{R} \\ \text{Multiply both sides by R} \\ I\cdot R=R\cdot\frac{V}{R} \\ IR=V \\ \text{divide both sides by I} \\ \frac{RI}{I}=\frac{V}{I} \\ R=\frac{V}{I} \end{gathered}$

Step 2

2

let

Power is equal to voltage multiplied by current.

so

$P=VI\rightarrow(1)$

also, replacing

$\begin{gathered} P=VI \\ P=(IR)I \\ P=RI^2\rightarrow(2) \\ \end{gathered}$

also

$\begin{gathered} V^2=I^2R^2 \\ \text{hece} \\ I^2=\frac{V^2}{R^2} \\ \\ \text{therefore, } \\ P=RI^2\rightarrow(2) \\ P=\frac{V^2}{R^2}\cdot R \\ P=\frac{V^2}{R} \end{gathered}$

I hope this helps you