Question

What is the point of instruction when the system of equations below is graphed on the cordinate plane?

Answer 1

To solve the given system, we have to multiply the first equation by -1.

$\begin{cases}x-y=-4 \\ 6x+y=-3\end{cases}$

Then, we combine the equations

$\begin{gathered} 6x+x+y-y=-4-3 \\ 7x=-7 \\ x=-\frac{7}{7} \\ x=-1 \end{gathered}$

Now, we find y

$\begin{gathered} x-y=-4 \\ -1-y=-4 \\ -y=-4+1 \\ -y=-3 \\ y=3 \end{gathered}$

Hence, the intersection point is (-1,3).