Question

Determine the reduction in volume when the temperature of 0.5 litre ofethyl alcohol is reduced from 40 °C to -15 °C.

Answer 1

Answer:

It is reduced to 0.41L

Explanation:

The volume and temperature have a directly proportional relationship. So, we can write the following equation

$\frac{V_2}{V_1}=\frac{T_2}{T_1}$

Now, we need to convert the temperatures 40 °C and -15 °C to kelvin, so

40°C + 273.15 = 313.15 K

-15 °C + 273.15 = 258.15 K

Then, we can replace the values as

$\frac{V_2}{0.5\text{ L}}=\frac{258.15\text{ K}}{313.15\text{ K}}$

Solve for V2

$\begin{gathered} V_2=\frac{258.15K}{313.15K}\cdot0.5L \\ V_2=0.41L_{}_{} \end{gathered}$

Therefore, the volume is reduced from 0.5 L to 0.41 L