Respuesta :

Note: w=x for the explanation.

Notice that we can rewrite the given trinomial as:

[tex]2\left(3x^2-14x+16\right).[/tex]

Now, we can write

[tex]3x^2-14x+16[/tex]

as

[tex](3x^2-6x)-(8x+16)=3x(x-2)-8(x-2).[/tex]

Finally, factoring out the (x-2), we get:

[tex]6x^2-28x+32=2(x-2)(3x-8).[/tex]

Answer:

[tex]6w^2-28w+32=2(w-2)(3w-8).[/tex]

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