Question

I attach my worksheet Suppose that a random variable X can take on integer values from 0 to 5 and its pdf is defined as follow p(x)=11-2x/36calculate p(x) for all possible values

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

x = 0 to 5

p(x) = (11 - 2x) / 36

Step 02:

calculate p(x):

integer values:

x = 0:

$p(0)=\frac{11-2(0)_{}}{36}=\frac{11}{36}$

x = 1:

$p(1)=\frac{11-2(1)}{36}=\frac{9}{36}=\frac{1}{4}$

x = 2:

$p(2)\text{ = }\frac{11-2(2)}{36}=\frac{11-4}{36}=\frac{7}{36}$

x = 3:

$p(3)\text{ = }\frac{11-2(3)}{36}=\frac{11-6}{36}=\frac{5}{36}$

x = 4:

$p(4)\text{ = }\frac{11-2(4)}{36}=\frac{11-8}{36}=\frac{3}{36}=\frac{1}{12}$

x = 5:

$p(5)\text{ = }\frac{11-2(5)}{36}=\frac{11-10}{36}=\frac{1}{36}$

That is the full solution.