We have the following:
[tex]log\: \frac{14}{3}+log\: \frac{11}{5}-log\: \frac{22}{15}=log\: x[/tex]
solving:
[tex]\begin{gathered} log(\: \frac{14}{3}\cdot\: \frac{11}{5})-\log \frac{22}{15}=\log x \\ log(\: \frac{154}{15})-\log \frac{22}{15}=\log x \\ log(\: \frac{\frac{154}{15}}{\frac{22}{15}})=\log x \\ \log 7=\log \text{ x} \\ \end{gathered}[/tex]
Therefore, the answer is log 7
