Given:
It is given that the length of a shadow of a building is 56 ft when the sun is 70° above the horizon.
Find:
we have to find the height of the building.
Explanation:
we know in trigonometry that
[tex]tan\theta=\frac{Perpendicular}{Base}[/tex]here angle is 70 degree, base is 56 ft.
Let h be the perpendicular, i.e. height of the building
Therefore, we get
[tex]\begin{gathered} tan70^o=\frac{h}{56} \\ h=56\times tan70^o \\ h=153.8\text{ }ft \end{gathered}[/tex]Therefore, the height of the building is 153.8 ft (by rounded to nearest tenth)