From the picture provided in this question, we can draw a straight line horizontally and the diagram would be divided into two different shapes, which are,
An isosceles trapezoid and
A quarter circle
The dimensions and area would now be;
[tex]\begin{gathered} \text{Isosceles Trapezoid:} \\ A=\frac{1}{2}(B_1+B_2)h \\ B_1=4,B_2=9,h=2 \\ A=\frac{1}{2}(4+9)\times2 \\ A=\frac{1}{2}(13)\times2 \\ A=13\operatorname{cm} \end{gathered}[/tex]The area of the quarter circle also would now be;
[tex]\begin{gathered} A=\pi\times r^2 \\ \text{For a quarter circle, the area would be times }\frac{1}{4} \\ A=\frac{1}{4}(\pi\times r^2) \\ \text{Where radius=}4\operatorname{cm} \\ A=\frac{1}{4}(3.14\times4^2) \\ A=\frac{1}{4}(3.14\times16) \\ A=3.14\times4 \\ A=12.56\operatorname{cm} \end{gathered}[/tex]The areaof the entire shape therefore is the addition of the area of the trapezoid and that of the quarter circle.
Area = 13 cm + 12.56 cm
Area = 25.56 square centimeters
