We have the following:
m, is the slope is 1/4 and goes through (-1,8)
Equation in slope-intercepr form is:
[tex]y=mx+b[/tex]for b:
[tex]\begin{gathered} 8=\frac{1}{4}\cdot-1+b \\ b=\frac{33}{4} \end{gathered}[/tex]therefore:
(a)
[tex]y=\frac{1}{4}x+\frac{33}{4}[/tex](b)
[tex]\begin{gathered} y-\frac{1}{4}x=\frac{33}{4} \\ 4y-x=33 \end{gathered}[/tex]