The question represents a binomial distribution.
The binomial probability formula is calculated using the formula:
[tex]P(X)=^nC_Xp^X(1-p)^{n-X}[/tex]where
P = binomial probability
X = number of times for a specific outcome within n trials
n C x = number of combinations
p = probability of success on a single trial
n = number of trials
From the question, we have the following parameters:
[tex]\begin{gathered} p=30\%=0.3 \\ n=10 \end{gathered}[/tex]We are to evaluate the probability that more than 5 and less than 9, hence:
[tex]P(5At X = 6:[tex]\begin{gathered} P(6)=^{10}C_6\cdot0.3^6\cdot(1-0.3)^{10-6} \\ P(6)=0.0368 \end{gathered}[/tex]At X = 7:
[tex]P(7)=0.0090[/tex]At X = 8:
[tex]P(8)=0.0014[/tex]Therefore, the probability will be:
[tex]P(5The probability is 0.0472.