Question

find the range of the quadratic function f(x)=(x+5)^2+2

Answer 1

Answer:

[2, ∞)

Explanation:

Given f(x) defined below:

$f(x)=(x+5)^2+2$

Compare the given quadratic function to the vertex form:

$f(x)=a(x-h)^2+k$$f(x)=a(x-h)^2+k$

The vertex of the function, (h,k)=(-5,2)

What this means is that the minimum value of f(x) is 2.

Therefore, the range of the quadratic function is:

$[2,\infty)$