Question

$19 \frac{4}{7} + 26 \frac{4}{5}$i need help solving this problem

Answer 1

We are going to add fractions.

$19\frac{4}{7}+26\frac{4}{5}$

First, let's convert them to improper fractions:

$19\frac{4}{7}=\frac{(19\cdot7)+4}{7}=\frac{133+4}{7}=\frac{137}{7}$

and

$26\frac{4}{5}=\frac{(26\cdot5)+4}{5}=\frac{130+4}{5}=\frac{134}{5}$

Now, we have:

$\frac{137}{7}+\frac{134}{5}$

We can take common denominator and add after that. The process is shown below:

$\begin{gathered} \frac{137}{7}(\frac{5}{5})+\frac{134}{5}(\frac{7}{7}) \\ =\frac{685}{35}+\frac{938}{35} \\ =\frac{685+938}{35} \\ =\frac{1623}{35} \end{gathered}$

Thus, the sum is:

$\frac{1623}{35}$