The radius,r, of the cylindrical swimming pool is 10/2 = 5m
By formula,
The volume of the swimming pool is;
[tex]V=\pi r^2h=3.14\times5^2\times1.2=94.2m^3[/tex]The number,n, of hours needed to empty the swimming pool at a rate of 19 cubic meters per hour:
[tex]n=\frac{\text{Volume}}{19}=\frac{94.2}{19}=4.958\approx5\text{ hours}[/tex]