SOLUTION
To answer the questions, we nee to find the volume of both shapes
Shape 1 is a rectangular pyramid.
Volume of shape 1 is
[tex]\begin{gathered} \text{Volume of a pyramid = }\frac{1}{3}\times base\text{ area }\times height\text{ } \\ The\text{ base of the rectangular pyramid is a rectangle } \\ \text{The base area = L }\times b=\text{ 3}\times4=12 \\ \text{The height h= 5} \\ \text{Volume of shape 1 = }\frac{1}{3}\times base\text{ area }\times height\text{ } \\ =\text{ }\frac{1}{3}\times12\text{ }\times5 \\ =\text{ 4 }\times5=20cm^3 \end{gathered}[/tex]
Volume of shape 2 is
[tex]\begin{gathered} \text{The base of shape 2 is a triangle } \\ \text{Area of the base = }\frac{1}{2}bh \\ =\text{ }\frac{1}{2}\times4\times3\text{ = 6cm} \\ \text{Volume = }\frac{1}{3}\times base\text{ area }\times height\text{ } \\ \text{Volume = }\frac{1}{3}\times6\text{ }\times5 \\ \text{Volume = 2 }\times\text{ 5 } \\ \text{Volume of shape 2 = 10cm}^3 \end{gathered}[/tex]
Therefore,
The volume of ice in shape 1 is 20
The volume of ice in shape 2 is 10
Shape 1 contains twice or two times the ice in shape 2