Question

In the diagram below of circle o, chords AB and CD intersect at e If m aec=34 and mAC=50 what is mDB

Answer 1

The inscribed angle AEC is half of the sum of the intercepted arcs AC and DB.

$34\degree=\frac{1}{2}(50\degree+DB)$

To eliminate the denominator, multiply both sides of the equation by 2.

$68\degree=50\degree+DB$

To solve for arc DB, subtract both sides of the equation by 50.

$18\degree=DB$

Thus, the measure of arc DB is 18°.