Explanation
The rectangular safe can hold 5184 cubic inches.
One gold bar has a volume of
[tex]volume=length\times width\times height=6\times3\times2=36[/tex]Therefore; the maximum number of goldbar will be.
[tex]maximum\text{ }number=\frac{volume\text{ }the\text{ }safe\text{ }can\text{ }hold}{volume\text{ of one gold bar}}=\frac{5184}{36}=144[/tex]Answer: 144