Answer:
16.7%
Explanation:
The number of faces in a die = 6
Multiples of 3, {3,6} = 2
[tex]P(m\text{ultiple of 3)}=\frac{2}{6}[/tex]The total number of cards in a standard deck = 52
Number of red cards = 26
[tex]\begin{gathered} P(\text{red card)=}\frac{26}{52} \\ =\frac{1}{2} \end{gathered}[/tex]Therefore, the probability that the die will be a multiple of 3 and the card will be red:
[tex]\begin{gathered} =\frac{2}{6}\times\frac{1}{2} \\ =0.16667 \\ =16.667\% \\ P(mult.\; of\; 3,red\; card)\approx16.7\%\text{ (to the nearest tenth)} \end{gathered}[/tex]
