if p || , m<7 = 131°, and m<16 = 88°, find the measure of the missing angle m<6= ?

The angle 7 is given as, m<7 = 131°.
The sum of angle 7 and angle 8 is, 180°.
Therefore,
[tex]m\angle7+m\angle8=180^{\circ}[/tex][tex]131^{\circ}+m\angle8=180^{\circ}[/tex][tex]m\angle8=49^{\circ}[/tex]The angle 8 is corresponding to angle 6 .
Since p is parallel to q and any pair of angles each of which is on the same side of one of two lines cut by a transversal and on the same side of the transversal are correspnding angles.
Hence , the angle m<6=m<8.
Thus, the value of m<6 is,
[tex]m\angle6=49^{\circ}[/tex]