Respuesta :
oh ok so it would be binomcdf( 500, 0.5, 450) so the end result would be 450?
Answer:
Option: D is the correct answer.
D. binomcdf(45, 0.5, 10)
Step-by-step explanation:
We are asked to find the probability that 10 or fewer heads come up when flipping a coin 45 times.
We know that the binomial probability distribution function of k successes for n experiments is given by:
[tex]P(X=k)=n_C_k\cdot p^k\cdot (1-p)^{n-k}[/tex]
Here we have: n=10
p=flipping of a head=1/2=0.5
k=0,1,2,3,4,5,6,7,8,9,10
i.e. r=10
Now binomcdf is a function which is defined as:
[tex]binomcdf(n,p,r)=P(X\leq r)=\sum_{k=0}^{r} P(X=k)[/tex]
Hence, by putting the values of n,p and r in the function we have:
The binomcdf function is given by:
D. binomcdf(45, 0.5, 10)