SOLUTION
1. We have
[tex]\begin{gathered} Triangle1\colon15\degree,45\degree \\ Triangle2\colon45\degree,120\degree \\ For\text{ Trinagle 1, 15 + 45 + 120 = }180,\text{ assume the 3rd angle is 120}\degree \\ \text{For Triangle 2, 45 + 120 + 15 = 180, assume the 3rd angle is }15\degree \end{gathered}[/tex]
Since we got 180 in both, hence the two trinagles are similar
2.
[tex]\begin{gathered} Triangle1\colon90\degree,45\degree \\ Triangle2\colon45\degree,45\degree \\ For\text{ Trinagle 1, 90 + 45 + 45 = }180,\text{ assume the 3rd angle is 45}\degree \\ \text{For Triangle 2, 45 + 45 + 90 = 180, assume the 3rd angle is 90}\degree \end{gathered}[/tex]
Since we got 180 in both, hence the two trinagles are similar
3.
[tex]\begin{gathered} Triangle1\colon130\degree,35\degree \\ Triangle2\colon25\degree,130\degree \\ For\text{ Trinagle 1, 130 + 35 + 25 = }190,\text{ assume the 3rd angle is 25}\degree \\ \text{For Triangle 2, 25 + 130 + 35 = 190, assume the 3rd angle is 35}\degree \end{gathered}[/tex]
Since we got 190, the two triangles are not similiar because the sum of interior angles in any triangle must be equal to 180 degrees
Hence the triangles in number 3 are NOT similar