Question

Question 7: For the probability distribution table below:x2x12345P®)0.210.170.220.110.29xP(x)x?P®1160.2 - 0.21 10-20 =0.2||2017=0.34 460-17)= 0 GB3/-22)-066 10-22 1.9840. (D=0.44 VOD 1.761560-19-1.455.0.291.75925a.Complete the table above.b.Find the mean y. Round to two decimal places.c.Find the standard deviation o. Round to three decimal places.

Answer 1

Solution

b and c

$\mu=\sum_^xP(x)=0.21+0.34+0.66+0.44+1.45=3.1$$\begin{gathered} \sigma^2=\sum_^x^2P(x)-(\sum_^xP(x))^2 \\ \\ \\ =(0.21+0.68+1.98+1.76+7.25)-(3.1)^2 \\ \\ =11.88-(3.1)^2=2.27 \\ \\ \Rightarrow\sigma=\sqrt{2.27}=1.507 \end{gathered}$