Respuesta :

[tex]2x-2=-x+10[/tex]

To solve this question you need to leave in one side of the equal all the terms with the variable (x) and in the other side the other terms:

- Add x in both sides of the equation

[tex]\begin{gathered} 2x+x_{}-2=-x+x+10 \\ 3x-2=10 \end{gathered}[/tex]

-Add 2 in both sides of the equation:

[tex]\begin{gathered} 3x-2+2=10+2 \\ 3x=12 \end{gathered}[/tex]

-Divide into 3 both sides of the equation:

[tex]\begin{gathered} \frac{3}{3}x=\frac{12}{3} \\ \\ x=4 \end{gathered}[/tex]Then, the solution for the given equation is x=4
RELAXING NOICE
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