Question

an arrow is shown below using a square and a triangle what is the area of the arrow?

Answer 1

To find the area of the arrow you sum the area of the square and the area of the triangle:

$A=A_s+A_{\Delta}$

Area of a square:

$A_s=s^2$

s is the measure of one side of the square

Area of a triangle:

$A_{\Delta}=\frac{1}{2}b\cdot h$

b is the measure of the base and h is the height of the triangle.

Then, the area of the arrow is:

$A=s^2+\frac{1}{2}b\cdot h$

s= 3ft

b= 3ft+2.5ft+2.5ft=8ft

h=5ft

$\begin{gathered} A=(3ft)^2+\frac{1}{2}(8ft)(5ft) \\ \\ A=9ft^2+\frac{40}{2}ft^2 \\ \\ A=9ft^2+20ft^2 \\ \\ A=29ft^2 \end{gathered}$Then, the area of the arrow is 29 square feet