Question

A rectangular pasture has a fence around the perimeter. The length of the fence is 16x^7 and the width is 48x^4. What is the area of the pasture?

Answer 1

A=LW
multily
remmber
$(x^m)(x^n)=x^{m+n}$
so
$(16x^7)(48x^4)=(16)(x^7)(48)(x^4)=$$(16)(48)(x^7)(x^4)(768)(x^{7+4})=768x^{11}$

Answer 2

Answer:

The area of the  rectangular pasture is $768x^{11}\ unit^{2}.$

Step-by-step explanation:

Formula

Area of a rectangle = Length ×  Breadth

As given

A rectangular pasture has a fence around the perimeter. The length of the fence is $16x^{7}$ and the width is $48x^{4}$.

Put all the values in the formula

$Area\ of\ a\ rectangular\ pasture = 16x^{7}\times 48x^{4}$

Now by using the exponent

$x^{a}\times x^{b} = x^{a+b}$

$Area\ of\ a\ rectangular\ pasture = 16\times 48\times (x^{7+4})$

$Area\ of\ a\ rectangular\ pasture = 768(x^{11})$

Therefore the area of the  rectangular pasture is $768x^{11}\ unit^{2}.$