Select a function f whose zeros are 0, negative 3, 2, and negative 4.

All the alternatives are polynomials. In a polynomial in factored form, each factor corresponds to a zero of the function.
If r is a zeros of the polynomial function, it will have a factor:
[tex](x-r)[/tex]So, if 0, -3, 2 and -4 are zeros of the polynomial, we have the factors:
[tex]\begin{gathered} (x-0)=x \\ (x-(-3))=(x+3) \\ (x-2) \\ (x-(-4))=(x+4) \end{gathered}[/tex]So, the function that has these zeros is:
[tex]f(x)=x(x+3)(x-2)(x+4)[/tex]