Recall that in a right triangle we know that:
[tex]\tan \theta=\frac{\text{opposite leg}}{adyacent\text{ leg}}.[/tex]
Therefore:
[tex]\tan 29^{\circ}=\frac{x}{15}.[/tex]
Multiplying the above equation by 15 we get:
[tex]\begin{gathered} \tan 29^{\circ}\times15=\frac{x}{15}\times15, \\ x=15\tan 29^{\circ}\text{.} \end{gathered}[/tex]
Answer:
[tex]x=15\tan 29^{\circ}.[/tex]
