Question

What is the probability of drawing two bluemarbles if the first marble is placed back inthe bag before the second draw?Give your answer as a rational number, reduced tosimplest terms.

Answer 1

Answer:

Given the information in the attached image;

The number of blue marbles is 5.

The total number of marbles is 10.

So, the probability of drawing blue as the first marble is;

$P_1=\frac{5}{10}=\frac{1}{2}$

Also, since there is a replacement, the probability of drawing blue as the second marble is;

$P_2=\frac{5}{10}=\frac{1}{2}$

the probability of drawing two blue marbles will be;

$\begin{gathered} P=P_1\times P_2 \\ P=\frac{1}{2}\times\frac{1}{2} \\ P=\frac{1}{4} \end{gathered}$

Therefore, the probability of drawing two blue marbles is;

$\frac{1}{4}$