Given:
The figure with some sides measurements.
Required:
What is missing side length and which triangle is a right triangle?
Explanation:
Converse of Pythagoras theorem:
[tex]\begin{gathered} \text{ If the length of a triangle is }a,b\text{ and }c\text{ and }c^2=a^2+b^2,\text{ then the triangle} \\ \text{ is a right angle triangle.} \end{gathered}[/tex]
So, take BAD right triangle,
[tex]\begin{gathered} BA^2+AD^2=BD^2 \\ 4^2+4^2=BD^2 \\ BD^2=16+16 \\ BD^2=32 \\ BD=4\sqrt{2} \end{gathered}[/tex]
Now,
[tex]\begin{gathered} \text{ In }\Delta CBD, \\ BC^2+BD^2=CD^2 \\ 2^2+(4\sqrt{2})^2=6^2 \\ 4+32=36 \\ 36=36 \end{gathered}[/tex]
Answer:
[tex]\begin{gathered} \text{ In diagram missing length equals }4\sqrt{2}\text{ and }\Delta BAD\text{ and }\Delta CBD\text{ are right} \\ triangles. \end{gathered}[/tex]