Question

ind the surface area of the trapezoidal prism below if AB = 16 cm, DE = 10 cm, AD = 12 cm, BE = 14 cm, DP = 8 cm, and BC = 17 cm

Answer 1

ANSWER:

c. 1092 cm^2

EXPLANATION:

Given:

Height of the prism, DP = 8 cm = h

Top width, DE = 10 cm = a

Base width, AB = 16 cm = b

Slant height, AD = 12 cm = c

Length of the prism, BC = 17 cm = l

Slant height, BE = 14 cm = d

We can go ahead and determine the surface area as seen below;

$\begin{gathered} Surface\text{ }Area=(a+b)h+(a+b+c+d)l \\ \\ =(10+16)8+(10+16+12+14)17 \\ \\ =(26)8+(52)17 \\ \\ =208+884 \\ \\ =1092\text{ cm}^2 \end{gathered}$

So the surface area of the prism is 1092 cm^2