Question

Given the following rule, calculate the first four terms of the sequence that starts with n = 0t = 3n + 2

Answer 1

Given:

t = 3n + 2​

To find the first four terms:

When n=0, we get

$\begin{gathered} t=0+2 \\ t=2 \end{gathered}$

When n=1, we get

$\begin{gathered} t=3(1)+2_{} \\ t=5 \end{gathered}$

When n=2, we get

$\begin{gathered} t=3(2)+2_{} \\ t=8 \end{gathered}$

When n=3, we get

$\begin{gathered} t=3(3)+2_{} \\ t=11 \end{gathered}$

Hence, the answers are,

When n=0, we get t=2

When n=1, we get t=5

When n=2, we get t=8

When n=3, we get t=11.