Explanation:
We can write a system of linear equations with this information.
• x: number of 25 cent stamps
,• y: number of 20 cent stamps
The system is:
[tex]\begin{gathered} x+y=40 \\ 0.25x+0.20y=9.60 \end{gathered}[/tex]Solving using the substitution method, we first clear y from the first equation:
[tex]y=40-x[/tex]Replace into the second equation:
[tex]0.25x+0.20(40-x)=9.60[/tex]And solve for x:
[tex]\begin{gathered} 0.25x+0.20\times40-0.20x=9.60 \\ 0.05x+8=9.60 \\ 0.05x=9.60-8 \\ x=\frac{1.6}{0.05}=32 \end{gathered}[/tex]Finally, replace x = 32 into the equation for y we cleared before to find the value of y:
[tex]y=40-x=40-32=8[/tex]Answer:
He bought:
• 32, ,25-cent stamps
,• 8 ,20-cent stamps