Question

Equation of a Perpendicular BisectorNov 30,9:58:45 PMWatch help video?Find an equation for the perpendicular bisector of the line segment whose endpointsare (-2,7) and (-8, -3).Answer:Submit Answerattempt 1 out of 3 / problem 1 out of max 1Privacy PolicyTerms of Service

Answer 1

First we are gonna calculate the slope

$\begin{gathered} m=\frac{-3-7}{-8+2} \\ m=\frac{-10}{-6} \\ m=\frac{5}{3} \end{gathered}$

Now, we are gonna calculate the midpoint

$\begin{gathered} (\frac{-2-8}{2},\frac{-3+7}{2}) \\ (\frac{-10}{2},\frac{4}{2}) \\ (-5,2) \\ \end{gathered}$

Equation

$\begin{gathered} y-2=-\frac{3}{5}(x+5) \\ y-2=-\frac{3}{5}x-3 \\ y=-\frac{3}{5}x-3+2 \\ \\ y=-\frac{3}{5}x-1 \end{gathered}$