In the following statement, express the first number as a percentage of the second numberThe 2016 revenue for Company A was $289 million, compared to $567 million for Company B.The 2016 revenue for Company A was % of the revenue for Company B.(Round to the nearest tenth as needed.)

Respuesta :

51 %

Explanation

to solve this we can use a rule of three

Step 1

set the proportion

[tex]\begin{gathered} x=renevue\text{ Company A compared as a percentate for company B} \\ \end{gathered}[/tex]

so,

[tex]\begin{gathered} \text{if } \\ $567$\text{ }\rightarrow\text{ 100\%} \\ 289\rightarrow x \end{gathered}[/tex]

the propotion is

[tex]\frac{567}{100}=\frac{289}{x}[/tex]

Step 2

solve for x

[tex]\begin{gathered} \frac{567}{100}=\frac{289}{x} \\ \text{cross multiply} \\ 567\cdot x=289\cdot100 \\ 567x=28900 \\ \text{divide both sides by 567} \\ \frac{567x}{567}=\frac{28900}{567} \\ x=50.970 \\ \text{rounded} \\ x=51 \end{gathered}[/tex]

therefore, the answer is 51%

I hope this helps you

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