Answer:
•x-intercept = 1
•y-intercept = -2
Explanation:
Given the linear equation
[tex]4x-2y=4[/tex]x-intercept
The x-intercept is the value where the line crosses the x-axis.
We calculate this by setting y=0
[tex]\begin{gathered} \text{When y=0} \\ 4x-2y=4 \\ 4x-2(0)=4 \\ 4x-0=4 \\ 4x=4 \\ \text{Divide both sides by 4} \\ \frac{4x}{4}=\frac{4}{4} \\ x=1 \end{gathered}[/tex]The x-intercept is 1.
We have the point (1, 0)
y-intercept
The y-intercept is the value where the line crosses the y-axis.
We calculate this by setting x=0
[tex]\begin{gathered} \text{When x=0} \\ 4x-2y=4 \\ 4(0)-2y=4 \\ -2y=4 \\ \text{Divide both sides by -2} \\ -\frac{2y}{-2}=\frac{4}{-2} \\ y=-2 \end{gathered}[/tex]The y-intercept is -2.
We have the point (0, -2)
We then plot the points on the graph below:
