Question

Use special right triangles to solve for the values of x. Round answer to the nearest tenth if necessary.

Answer 1

By Trigonometric Ratio,

$\begin{gathered} \sin 60=\frac{5\sqrt[]{3}}{x} \\ \text{Cross multiply to get,} \\ x=\frac{5\sqrt[]{3}}{\sin 60}=\frac{5\sqrt[]{3}}{\frac{\sqrt[]{3}}{2}} \\ \\ x=\frac{2\times5\sqrt[]{3}}{\sqrt[]{3}}=2\times5=10 \end{gathered}$

So, the value of x is 10.