Respuesta :

Solution

For this case we have the following equation:

[tex]x^2+2x+30=0[/tex]

We can complete the square with the following:

[tex]x^2+2x+(\frac{2}{2})^2+30-(\frac{2}{2})^2=0[/tex]

And solving we got:

[tex]x^2+2x+1+30-1=0[/tex]

Then the answer for this case should be:

1

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