If the triangle shown, The angle CAB = 30° and AC =50m. What is the length of BC is?

GIVEN:
We are given a right angle as shown in the attached image. For triangle ABC, we have;
[tex]\angle A=30\degree,\text{ }AC=50m[/tex]Required;
To find the length of side AC.
Step-by-step solution;
For a right angled triangle with respect to the reference angle, the sides are labeled as follows;
[tex]\begin{gathered} Reference\text{ }angle=30\degree \\ \\ Opposite=BC \\ \\ Adjacent=AB \\ \\ Hypotenuse=AC \end{gathered}[/tex]To find the length of BC (opposite), given the length of AC (hypotenuse), we shall use the ratio;
[tex]sin\theta=\frac{opposite}{hypotenuse}[/tex]We now use the values provided and we have;
[tex]sin30\degree=\frac{BC}{50}[/tex]Now we cross multiply;
[tex]\begin{gathered} 50\times sin30=BC \\ \\ 50\times0.5=BC \\ 25=BC \\ \end{gathered}[/tex]ANSWER:
[tex]BC=25[/tex]