Question

What are the roots of the equation?(x-3)(x+2)(x-1)= 0

Answer 1

Given a polynomial P(x), if we know the roots a, b and c then we can rewrite the polynomial as:

$P(x)=(x-a)(x-b)(x-c)$

In this case, we are given:

$(x-3)(x+2)(x-1)=0$

Then, we can find the roots, multiplying the constant inside the parentheses by (-1):):

$\begin{gathered} First\text{ }root=(-1)(-3)=3 \\ Second\text{ }root=(-1)\cdot2=-2 \\ Third\text{ }root=(-1)(-1)=1 \end{gathered}$

Roots: -2, 1, 3