[tex]\begin{gathered} \text{The equation of line is,} \\ y=\frac{1}{2}x+3 \\ \text{Compare the given equation with equation of line}\Rightarrow y=mx+b \\ So,\text{ slope}\Rightarrow m=\frac{1}{2} \\ \text{Now, the given point is }\Rightarrow(-3,5) \\ \text{The equation in slope-intercept form is,} \\ y-y_1=m(x-x_1) \\ y-5=\frac{1}{2}(x+3) \\ 2y-10=x+3 \\ 2y=x+13 \\ y=\frac{1}{2}x+\frac{13}{2} \end{gathered}[/tex]
