Respuesta :

The given area is

[tex]A=x^3+4x^2-11x-30[/tex]

The length is

[tex]L=x^2-x-6[/tex]

Since the rule of the area ofthe rectangle is

[tex]A=L\times W[/tex]

Then to find the width, divide the area b the length

[tex]\begin{gathered} W=\frac{A}{L} \\ \\ W=\frac{x^3+4x^2-11x-30}{x^2-x-6} \end{gathered}[/tex]

We will just divide thefirst terms and thelst terms to find the answer

[tex]\begin{gathered} \frac{x^3}{x^2}=x \\ \frac{-30}{-6}=5 \end{gathered}[/tex]

Then the width is

[tex]W=x+5[/tex]

The answer is B

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