Need to find the expression that represents the width !

The given area is
[tex]A=x^3+4x^2-11x-30[/tex]The length is
[tex]L=x^2-x-6[/tex]Since the rule of the area ofthe rectangle is
[tex]A=L\times W[/tex]Then to find the width, divide the area b the length
[tex]\begin{gathered} W=\frac{A}{L} \\ \\ W=\frac{x^3+4x^2-11x-30}{x^2-x-6} \end{gathered}[/tex]We will just divide thefirst terms and thelst terms to find the answer
[tex]\begin{gathered} \frac{x^3}{x^2}=x \\ \frac{-30}{-6}=5 \end{gathered}[/tex]Then the width is
[tex]W=x+5[/tex]The answer is B