Question

One 10.0 Ω resistor is wired in series with two 10.0 Ω resistors in parallel. A 45.0 V battery supplies power to the circuit. What is the total current through the circuit?0.75 A3.0 A0.33 A1.5 A

Answer 1

First, we need to find the equivalent resistance and then we will find the current

R2 and R3 are in parallel so the resistance will be

$R_2R_3=\frac{1}{\frac{1}{10}+\frac{1}{10}}=5$

then R1, R2R3, and R4 are in series so the resistance equivalent to this circuit will be

$\operatorname{Re}=10+5+10=25\Omega$

then we will use the law of ohm to find the current A1

$I=\frac{60}{25}=2.4A$

the ammeter A1 will read 2.4A.