Question

After surgery a patient has been asked to consume a low Calorie diet. For the first meal a protein bar was consumed containing 25g of carbohydrates, 18 g of protein, and 10 g of fat. For the second meal a banana containing 15 g of carbohydrates and an oatmealcontaining 48 g of carbohydrates, 16 g of protein, and 5 g of fat. If carbohydrates contain 4 Cal/g, fats 9 Cal/g and protein 4 Callg,a) how much energy did the patient consume? Round to the nearest one if necessary.b) what is the unit symbol for the answer?

Answer 1

SOLUTION

Write out the information given in the question

Protein meal contains

25g of carbohydrates, 18 g of protein, and 10 g of fat.

Second meal contains

15 g of carbohydrates.

oatmeal contains

48 g of carbohydrates, 16 g of protein, and 5 g of fat.

The total of each nutrient of each meal is

$\begin{gathered} Carbohydrates=25g+15g+48g=88g \\ \text{Protein}=18g+16g=34g \\ \text{fats =10g+5g=15g} \end{gathered}$

From the question, amount of energy contains in each nutrient is given as

$\begin{gathered} \text{Carbohydrate}=4\text{ cal/g} \\ \text{Protein}=4\text{ cal/g} \\ \text{Fats =9 cal/g} \end{gathered}$

Then, we obtain the calories in each of the nutrient.

Hence

For carbohydrates, we have

$\begin{gathered} 1g\text{ contains 4cal} \\ 889\text{ will contains=88 }\times4=352cal \end{gathered}$

Then

For Proteins, we have

$\begin{gathered} 1\text{ g contains 4 cal} \\ 34g\text{ will contains= 34}\times4=136cal \end{gathered}$

For fats, we have

$\begin{gathered} 1g\text{ contains 9cal} \\ 15\text{g will contains =15}\times9=135cal \end{gathered}$

Hence

The total energy consume by the patient will be the sum of the energy consume from each nutirent, then

$352\text{cal}+136\text{cal}+135\text{cal}=623\text{cal}$

Hence

The energy consume by the patient is 623calories

The units calories(cal).