Question

probability of who many yellow candy does Jessica grab from each bag

Answer 1

Bag A

Blue candy = 6

Yellow candy = 2

Bag B

Blue candy = 5

Yellow candy = 5

We want the probability that Jessica grabs a yellow candy from each bag. That is ---

Probability of Yellow from Bag 1 AND Probability of Yellow from Bag 2

****** Recall that "AND" in probability means to "MULTIPLY".

Let's denote probability of yellow from Bag A as P(YBA) and probability of yellow from Bag B as P(YBB).

Let's find each and then multiply them.

• P(YBA) >>> There are total 6 + 2 = 8 candies out of which "2" are yellow, thus,

$P(\text{YBA)}=\frac{2}{8}=\frac{1}{4}$

• P(YBB) >>> There are a total of 5 + 5 = 10 candies out of which "5" are yellow, thus,

$P(\text{YBB)}=\frac{5}{10}=\frac{1}{2}$

The correct answer is

$\frac{1}{4}\times\frac{1}{2}=\frac{1}{8}$Answer$\frac{1}{8}=0.125$