Notice that, since the first term is (x+2)^2, we dealing with a hyperbola that is parallel to the x-axis and centered in (-2,3).
The general form of a hyperbola centered in (c,d), and parallel to the x-axis is:
[tex]\frac{(x-c)^2}{a^2}-\frac{(y-d)^2}{b^2}=1[/tex]Where a is the horizontal distance between the center of the hyperbola and the vertices.
Then, in our case:
[tex]\begin{gathered} (-2,3)\to\text{center} \\ a=\pm4 \\ \Rightarrow(-2-4,3)=(-6,3),(-2+4,3)=(2,3)_{} \\ \text{are the vertices} \end{gathered}[/tex]The answer is (-6,3) and (2,3), the second option
